Developer FAQ
If I use the std. XSLT approach using <xsl:copy-of select=”/” /> the XML output gets ‘examined’ by C1 and in certain situations ‘transformed’ before it ends up as XHTML on my browser. How can I get a completely “raw” copy of the XML that is given to my XSLT?
Answer:
You can download and use the XSLT document Dump raw XSLT input.xslt.
The <xsl:copy-of /> construct wont show you “the read deal” in a situation, where parameters of your XSLT Function are fed items like <rendering: placeholder /> or certain function call results. This is because C1 is giving your XSLT an “intermediate document structure” which has not yet been normalized / ASP.NET enabled.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="xsl in msxsl csharp"
xmlns:in="http://www.composite.net/ns/transformation/input/1.0"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:csharp="http://c1.composite.net/sample/csharp"
xmlns="http://www.w3.org/1999/xhtml">
<xsl:template match="/">
<html>
<head />
<body>
<pre>
<xsl:copy-of select="csharp:GetAsString(/)" />
</pre>
</body>
</html>
</xsl:template>
<msxsl:script implements-prefix="csharp" language="C#">
<msxsl:assembly name="System.Xml.Linq"/>
<msxsl:using namespace="System.Xml.Linq"/>
<msxsl:using namespace="System.Xml"/>
<msxsl:using namespace="System.Xml.XPath"/>
public string GetAsString(XPathNavigator nav)
{
return XDocument.Parse( nav.OuterXml ).ToString();
}
</msxsl:script>
</xsl:stylesheet>